Codewars: Last digits of N^2 == N

Link to this kata

这个题还是挺有意思的, 与数学联系比较密切

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Python: Handle binary data

165089struct module: pack, unpack

struct

struct.pack(fmt, v1, v2, )

Return a bytes object containing the values v1, v2, … packed according to the format string fmt. The arguments must match the values required by the format exactly.

 

struct.unpack(fmt, buffer)

Unpack from the buffer buffer (presumably packed by pack(fmt, ...)) according to the format string fmt. The result is a tuple even if it contains exactly one item. The buffer’s size in bytes must match the size required by the format

 

struct.calcsize(fmt)

Return the size of the struct (and hence of the bytes object produced bypack(fmt, ...)) corresponding to the format string fmt.

 

fmt table:

Screen Shot 2017-09-21 at 16.54.52

Example:

>>> import struct
>>> struct.pack('B', 65)
b'A'
>>> struct.pack('BB', 65, 66)
b'AB'

>>> struct.unpack('h', b'A')     # refer to the table above
Traceback (most recent call last):
 File "<pyshell#8>", line 1, in <module>
 struct.unpack('h', b'A')
struct.error: unpack requires a bytes object of length 2

>>> struct.unpack('h', b'AB')    # correct
(16961,)

>>> struct.pack('hhl', 11, 22, 33)
b'\x0b\x00\x16\x00\x00\x00\x00\x00!\x00\x00\x00\x00\x00\x00\x00'
>>> struct.unpack('hhl', b'\x0b\x00\x16\x00\x00\x00\x00\x00!\x00\x00\x00\x00\x00\x00\x00')
(11, 22, 33)

>>> struct.calcsize('hhhhhlllB')
41